From programmr.com:
"Write a program which accepts 3 integers and sort them in ascending order."
Of course, we can use the ternary operator or some if/else statements in order to find the largest and smallest of the three numbers, respectively.
Once done that, we need to find the intermediate value using if/else statements.
The code and the print screen:
Anonther solution, using just if/else nested statements:
//sorting three without arrays v2.0
"Write a program which accepts 3 integers and sort them in ascending order."
Of course, we can use the ternary operator or some if/else statements in order to find the largest and smallest of the three numbers, respectively.
Once done that, we need to find the intermediate value using if/else statements.
The code and the print screen:
// sorting three numbers without arrays
#include <iostream>
using namespace std;
int main()
{
int a, b,
c, min, max, inter;
cout
<<"Gimmie three numbers and I will sort them for you.\nNumber a:
";
cin
>> a;
cout
<<"Number b: ";
cin
>> b;
cout
<<"Number c: ";
cin
>> c;
min = (a
<= b)?a : b;
min = (min
<= c)?min : c;
max = (a
>= b)?a : b;
max = (max
>= c)?max : c;
if((a
<= b && b <= c) || (c <= b && b <= a)) inter = b;
if((a
<= c && c <= b) || (b <= c && c <= a)) inter = c;
if((b <=
a && a <= c) || (c <= a && a <= b)) inter = a;
cout
<< min <<" "<< inter <<" "<<
max;
return 0;
}
//sorting three without arrays v2.0
#include <iostream>
using namespace std;
int main()
{
int a, b,
c, min, inter, max;
cout
<<"Gimmie three numbers and I will sort them ascending for you.\nNumber a: ";
cin
>> a;
cout
<<"Number b: ";
cin
>> b;
cout
<<"Number c: ";
cin
>> c;
if(a <=
b)
{
if(b
<= c)
{
inter = b; min = a; max = c;
}
else
{
max = b;
if(c > a)
{
inter = c;
min = a;
}
else
{
inter = a;
min = c;
}
}
}
else if (b
>= c)
{
max =
a;
min =
c;
inter
= b;
}
else
{
min =
b;
if(a
>= c)
{
max = a;
inter = c;
}
else
{
max = c;
inter = a;
}
}
cout
<< min <<" "<< inter <<" "<<
max;
return 0;
}
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